citra/src/common/hash.h
2018-08-07 19:34:47 -04:00

72 lines
2.5 KiB
C++

// Copyright 2015 Citra Emulator Project
// Licensed under GPLv2 or any later version
// Refer to the license.txt file included.
#pragma once
#include <cstddef>
#include <cstring>
#include "common/cityhash.h"
#include "common/common_types.h"
namespace Common {
/**
* Computes a 64-bit hash over the specified block of data
* @param data Block of data to compute hash over
* @param len Length of data (in bytes) to compute hash over
* @returns 64-bit hash value that was computed over the data block
*/
static inline u64 ComputeHash64(const void* data, size_t len) {
return CityHash64(static_cast<const char*>(data), len);
}
/**
* Computes a 64-bit hash of a struct. In addition to being trivially copyable, it is also critical
* that either the struct includes no padding, or that any padding is initialized to a known value
* by memsetting the struct to 0 before filling it in.
*/
template <typename T>
static inline u64 ComputeStructHash64(const T& data) {
static_assert(std::is_trivially_copyable_v<T>,
"Type passed to ComputeStructHash64 must be trivially copyable");
return ComputeHash64(&data, sizeof(data));
}
/// A helper template that ensures the padding in a struct is initialized by memsetting to 0.
template <typename T>
struct HashableStruct {
// In addition to being trivially copyable, T must also have a trivial default constructor,
// because any member initialization would be overridden by memset
static_assert(std::is_trivial_v<T>, "Type passed to HashableStruct must be trivial");
/*
* We use a union because "implicitly-defined copy/move constructor for a union X copies the
* object representation of X." and "implicitly-defined copy assignment operator for a union X
* copies the object representation (3.9) of X." = Bytewise copy instead of memberwise copy.
* This is important because the padding bytes are included in the hash and comparison between
* objects.
*/
union {
T state;
};
HashableStruct() {
// Memset structure to zero padding bits, so that they will be deterministic when hashing
std::memset(&state, 0, sizeof(T));
}
bool operator==(const HashableStruct<T>& o) const {
return std::memcmp(&state, &o.state, sizeof(T)) == 0;
};
bool operator!=(const HashableStruct<T>& o) const {
return !(*this == o);
};
size_t Hash() const {
return Common::ComputeStructHash64(state);
}
};
} // namespace Common